Unit 2 · Topic 2.11 · about 30 minutes

The Normal Distribution

Describe a normal distribution, find the probability for any interval and the cutoff for any area, and compare relative positions using percentiles.

Predict first

Suppose the heights of adult women in a country are approximately normal with mean 64 inches and standard deviation 2.7 inches. About what share of these women are 6 feet (72 inches) tall or taller?

Continuous random variables

A continuous random variable can take any value within a specified domain, such as a height or a time. You cannot list its values one by one, as you could for the discrete variables in 2.8 Introduction to Random Variables and Probability Distributions. Instead, every interval of values has a probability, and that probability is the area under a curve above the interval. The total area under the curve is 1.

A single exact value has no width, so it has no area. For a continuous variable, P(X<72) and P(X≤72) are the same number.

The normal distribution

Many continuous variables are well modeled by a normal distribution: a continuous, unimodal, bell-shaped, symmetric curve. A normal curve can model a distribution of data, like the heights of the women in a survey, or a random variable, like the height of one woman chosen at random.

Two parameters identify a normal distribution: the mean μ, which sits at the center, and the standard deviation σ, which sets the spread. The smaller the standard deviation, the taller the curve and the more tightly it is concentrated around the mean. The larger the standard deviation, the shorter and wider it is. The area stays 1 either way, so a curve that spreads out has to come down.

The standard normal distribution is the normal distribution with μ=0 and σ=1. A z-score from 1.9 Comparisons of the Distributions for One Quantitative Variable moves any normal value onto it: z=x−μσ.

The empirical rule

For any normal distribution, approximately 68% of values lie within 1 standard deviation of the mean, approximately 95% lie within 2, and approximately 99.7% lie within 3. This is the empirical rule, or the 68-95-99.7 rule. It gives quick estimates with no calculator.

Heights of adult women in inches: the middle 68%

55.958.661.36466.769.472.1z = −3z = −2z = −1z = 0z = 1z = 2z = 3

About 68% of heights fall between 61.3 and 66.7 inches, within one standard deviation of the mean.

The empirical rule for heights with mean 64 and standard deviation 2.7 inches
WithinInterval of heightsApproximate share
1 standard deviation61.3 to 66.7 inches68%
2 standard deviations58.6 to 69.4 inches95%
3 standard deviations55.9 to 72.1 inches99.7%

Areas from technology or a table

For an interval the empirical rule does not cover, use technology or a table. On a calculator, normalcdf(lower, upper, μ, σ) gives the area between two values; use a very large number, or infinity, for an open end. By hand, convert to a z-score and read Table A, which gives the area to the left of z under the standard normal curve.

Worked exampleHow long does the battery last?

The battery life of one phone model on a full charge is approximately normal with mean 22 hours and standard deviation 2.5 hours. Find the probability that a randomly chosen phone lasts more than 25 hours, and the probability that it lasts between 20 and 24 hours.

  1. Name the distribution and sketch it. Battery life X is normal with μ=22 and σ=2.5 hours. Draw the curve, mark 22 in the middle, and shade to the right of 25 for the first question.

  2. More than 25 hours. z=25−222.5=1.20. Table A gives 0.8849 to the left of z=1.20, so the area to the right is 1−0.8849=0.1151. On a calculator: normalcdf(25, 1E99, 22, 2.5) ≈0.1151.

  3. Between 20 and 24 hours. The z-scores are 20−222.5=−0.80 and 24−222.5=0.80. Table A gives an area between of 0.7881−0.2119=0.5762. A calculator gives normalcdf(20, 24, 22, 2.5) ≈0.5763. The last digit differs because Table A rounds each area to four decimal places.

  4. Interpret in context. About 11.5% of these phones last more than 25 hours on a charge, and about 57.6% last between 20 and 24 hours.

Answer.

P(X>25)≈0.1151 and P(20<X<24)≈0.576.

Battery life in hours: P(X > 25)

14.51719.52224.52729.5z = −3z = −2z = −1z = 0z = 1z = 2z = 3

The shaded right tail is about 0.1151 of the total area.

Working backward: from an area to a cutoff

Sometimes you know the area and need the boundary: what battery life marks the top 10%? invNorm(area, μ, σ) returns the value with that much area to its left. The top 10% has 90% of the area to its left, so the cutoff is invNorm(0.90, 22, 2.5) ≈25.20 hours. By hand, find z≈1.28 in the body of Table A and convert back: x=μ+zσ=22+1.28(2.5)≈25.2.

Every question of this kind matches one of four region shapes. Set up the area statement first, then the calculator command follows from it.

Four kinds of region, using battery life with mean 22 and standard deviation 2.5 hours
RegionArea statementCutoffsCalculator
Lowest 10%P(X<xa)=0.10below 18.80 hoursinvNorm(0.10, 22, 2.5)
Highest 10%P(X>xb)=0.10above 25.20 hoursinvNorm(0.90, 22, 2.5)
Middle 80%P(xa<X<xb)=0.8018.80 to 25.20 hoursinvNorm(0.10, ...) and invNorm(0.90, ...)
Most extreme 5%, split between the two tailsP(X<xa)=0.025 and P(X>xb)=0.025below 17.10 or above 26.90 hoursinvNorm(0.025, ...) and invNorm(0.975, ...)

Battery life in hours: the top 10%

14.51719.52224.52729.5z = −3z = −2z = −1z = 0z = 1z = 2z = 3

The cutoff, 25.20 hours, has 90% of the area to its left and 10% to its right.

Working backward to the mean or standard deviation

The z-score link also runs the other way, when a parameter is the unknown. A company wants only 5% of its phones to die before 18 hours, and its process gives a standard deviation of 2.5 hours. The 5th percentile sits at z= invNorm(0.05) ≈−1.645, so 18 hours must be 1.645 standard deviations below the mean:

18=μ−1.645(2.5),soμ≈22.11 hours

When the mean is known and the standard deviation is not, solve z=x−μσ for σ in the same way.

Comparing relative positions

Percentiles let you compare values from different normal distributions. Jordan throws the discus 40 meters in a league where throws are approximately normal with mean 34 and standard deviation 4.5 meters. Priya long-jumps 5.6 meters in a league where jumps are approximately normal with mean 5.0 and standard deviation 0.4 meters.

Jordan's throw has z=40−344.5≈1.33 and beats about 90.9% of throws. Priya's jump has z=5.6−5.00.4=1.50 and beats about 93.3% of jumps. Relative to her league, Priya's performance is the more impressive one, even though 5.6 and 40 cannot be compared directly.

Lab

Normal Curve Explorer

Set the mean to 0 and the standard deviation to 1 and check the empirical rule for yourself. Then double the standard deviation without moving the cutoffs and predict, before you look, whether the shaded area grows or shrinks.

Open the full Normal Curve Explorer lab

Check your understanding

1

Two normal curves have the same mean. Curve A has standard deviation 5 and curve B has standard deviation 10. Which statement is true?

2

Commute times at a large company are approximately normal with mean 30 minutes and standard deviation 6 minutes. Using the empirical rule, about what percent of commutes are between 18 and 36 minutes?

3

A coffee machine pours amounts that are approximately normal with standard deviation 0.2 ounces, and the owner can set the mean. What mean should she set so that only 2% of cups get less than 12 ounces? Round to two decimal places.

4

In an online game, reaction times are approximately normal with mean 250 milliseconds and standard deviation 30 milliseconds. Players with the fastest 5% of reaction times earn a badge. What is the cutoff time for the badge?

5

Maya runs the 1600 meters in 340 seconds, in a league where times are approximately normal with mean 380 seconds and standard deviation 25 seconds. Jordan throws the discus 40 meters, in a league where throws are approximately normal with mean 34 meters and standard deviation 4.5 meters. Relative to their own leagues, who had the better performance?

Practice

Practice until it is automatic

New numbers every time. Each one is checked the moment you answer, with the full working shown.

Normal distribution probabilities practice page · Percentiles of a normal distribution practice page · z-scores and relative position practice page

Course alignment, for teachers

AP Statistics topic 2.11, Unit 2: Probability, Random Variables, and Probability Distributions.

  • Skill 3.C: Calculate and estimate expected counts, percentages, probabilities, and intervals.
  • Skill 3.D: Calculate means, standard deviations, and parameters for probability distributions.
  • Skill 4.C: Describe distributions and compare relative positions of points within a distribution.